b^2+b-132=0

Solution for b^2+b-132=0 equation:

Simplifying
b2 + b + -132 = 0

Reorder the terms:
-132 + b + b2 = 0

Solving
-132 + b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-12 + -1b)(11 + -1b) = 0

Subproblem 1
Set the factor '(-12 + -1b)' equal to zero and attempt to solve:

Simplifying
-12 + -1b = 0

Solving
-12 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1b = 0 + 12
-1b = 0 + 12

Combine like terms: 0 + 12 = 12
-1b = 12

Divide each side by '-1'.
b = -12

Simplifying
b = -12
Subproblem 2
Set the factor '(11 + -1b)' equal to zero and attempt to solve:

Simplifying
11 + -1b = 0

Solving
11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1b = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1b = 0 + -11
-1b = 0 + -11

Combine like terms: 0 + -11 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11
Solution
b = {-12, 11}